(x^2 3x)^2-5(x^2 3x)-y(x^2 3x) 5y 116817

X 2 1 2 2 4 n 1 1 h2 1 6h h 1 3 4h 1 12 h 1 6 a3 2 a2 a3 a2 a 2 1 3(h 1 2) h 1 3 4 h 1 2 h 1 3 4p 1 16 5p p 1 4 15p3 5y3 7 ?Simple and best practice solution for 3x2=5(x1) equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so 3x 2 ˗ 4x 3x ˗ 4 = x(3x ˗ 4) 1 (3x ˗ 4) = (3x ˗ 4) (x 1) To find the zeroes, set f(x) = 0 (3x ˗ 4) = 0 or (x 1) = 0 x = 4/3 or x=1 So, the zeroes of f(x) are 4/3 and x=1 Again, Sum of zeroes = 4/3 (1) = 1/3 = b/ = Constant term

Solve The Following System Of Equations By Matrix Chegg Com

(x^2 3x)^2-5(x^2 3x)-y(x^2 3x) 5y

√99以上 (x^2 y^2-1)^3-x^2y^3=0 solve for y 488208-X2 2xy y2 3x 3y

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 1 Answer Cesareo R x3 −x2y −y3 xy2 = (x −y)(x2 y2) Explanation x3 −x2y −y3 xy2 = y3(( x y)3 − ( x y)2 ( x y) −1) but z3 −z2 z − 1 = 0 has a root z = 1 making z3 −z2 z − 1 = (z −1)(bz2 cz d) equating the coefficients we find ⎧⎪ ⎪ ⎪ ⎪ ⎨⎪ ⎪ ⎪ ⎪⎩d − 1 = 0 c − d 1 = 0 b − c − 1 = 0 1 − b = 0 solving for b,c,dX^2(y(x^2)^(1/3))^2 = 1 Natural Language;

X2 2xy y2 3x 3y